iz^2+2z+(1-i)=0

Solution for iz^2+2z+(1-i)=0 equation:

Simplifying
iz2 + 2z + (1 + -1i) = 0

Remove parenthesis around (1 + -1i)
iz2 + 2z + 1 + -1i = 0

Reorder the terms:
1 + -1i + iz2 + 2z = 0

Solving
1 + -1i + iz2 + 2z = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1i + iz2 + -1 + 2z = 0 + -1

Reorder the terms:
1 + -1 + -1i + iz2 + 2z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1i + iz2 + 2z = 0 + -1
-1i + iz2 + 2z = 0 + -1

Combine like terms: 0 + -1 = -1
-1i + iz2 + 2z = -1

Add '-2z' to each side of the equation.
-1i + iz2 + 2z + -2z = -1 + -2z

Combine like terms: 2z + -2z = 0
-1i + iz2 + 0 = -1 + -2z
-1i + iz2 = -1 + -2z

Reorder the terms:
1 + -1i + iz2 + 2z = -1 + -2z + 1 + 2z

Reorder the terms:
1 + -1i + iz2 + 2z = -1 + 1 + -2z + 2z

Combine like terms: -1 + 1 = 0
1 + -1i + iz2 + 2z = 0 + -2z + 2z
1 + -1i + iz2 + 2z = -2z + 2z

Combine like terms: -2z + 2z = 0
1 + -1i + iz2 + 2z = 0

The solution to this equation could not be determined.